Question

Solve:
$f\left(x\right)=\sin x-\cos x,0<x<2\pi$ ,find the required points

Answer 1

Given $f\left(x\right)=\sin x-\cos x$ ,$0<x<2\pi$

$f\left(x\right)=0\Rightarrow \sin x-\cos x=0$ or $\sin x=\cos x$

We plot graphs of $\sin x$ and $\cos x$ simentaneously in order to find the solution to find the points where $\sin x=\cos x$ in $0<x<2\pi$.

Hence required points are $\frac{\pi }{4}$ and $\frac{5\pi }{4}$