Solve following equation :
$x^{2} + x - 2 = 0$

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Solution

Finding the solution for equation:
Given, $x^{2} + x - 2 = 0$
$x^{2} + 2 x - x - 2 = 0$
$x (x + 2) - 1 (x + 2) = 0$
$(x - 1) (x + 2) = 0$
$x - 1 = 0 \Rightarrow x = 1 x + 2 = 0 \Rightarrow x = - 2$
Hence, value of $x$ are $1, - 2 .$

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