Question

Solve for : $-12<4+\frac{3x}{(-5)}\le 2$

Answer 1

$-12<4+\frac{3x}{(-5)}\le 2$

Multiply with $-5$ we get,

$⟹-12\times -5>4\times (-5)+3x\ge 2\times (-5)$

$⟹60>3x-20\ge -10$

$⟹60+20>3x-20+20\ge -10+20$

$⟹80>3x\ge 10$

$⟹10\le 3x<80$

$⟹\frac{10}{3}\le x<\frac{80}{3}$

$\therefore x\in [\frac{10}{3},\frac{80}{3})$