Solve for a- 3 a -4-5 a -2-14A- 0B- 1C- -1D- -2

The correct option is C 1 Given 3(a + 4) + 5(a + 2) = 14 ⇒ 3a +12 +5a +10 = 14 [Removing the brackets] [rearranging the terms] ⇒ 3a + 5a +12 +10 = 14 ⇒ ...

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Byju's Answer

Standard VI

Mathematics

Solving Equations ax = b and (x/a) = b by Rearranging Terms

Solve for a: ...

Question

Solve for $a$ : $3 (a + 4) + 5 (a + 2) = 14$

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Solution

The correct option is C
-1

Given $3 (a + 4) + 5 (a + 2) = 14$

$\Rightarrow 3 a + 12 + 5 a + 10 = 14$ [Removing the brackets]

[rearranging the terms]

$\Rightarrow 3 a + 5 a + 12 + 10 = 14$

$\Rightarrow 8 a + 22 = 14$

$\Rightarrow 8 a = 14 - 22$ [when +22 is transposed to RHS it becomes -22]

$\Rightarrow 8 a = - 8$

[dividing both terms by 8]

$\frac{8 a}{8} = a = \frac{- 8}{8} = - 1$

$\Rightarrow a = - 1$

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Solve for a: 3(a+4)+5(a+2)=14

The correct option is C -1 Given 3(a+4)+5(a+2)=14 ⇒3a+12+5a+10=14 [Removing the brackets] [rearranging the terms] ⇒3a+5a+12+10=14 ⇒8a+22=14 ⇒8a=14−22 [when +22 is transposed to RHS it becomes -22] ⇒8a=−8 [dividing both terms by 8] 8a8=a=−88=−1 ⇒a=−1

Solve for $a$ : $3 (a + 4) + 5 (a + 2) = 14$