Question

Solve for $A$ : $(sinA-1)(2cosA-1)=0$

Find the possible number of values of $A$ :

Answer 1

$(\sin A-1)(2\cos A-1)=0$
Either $\sin A=1$ or $2\cos A=1$
$A={90}^{\circ }$ or $A={30}^{\circ }$

Thus the number of possible values of $A$ is $2$.