Solve for - which satisfy- max- - R5 sin -3 sin-7

The correct option is C α=2n π±π/3 max _θ∈ R { 5sinθ #160; +3sin( θ α #160;) #160; #160;} #160; =7 ⇒max _θ∈ R { 5sinθ #160; +3sinθ ...

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Properties of Determinants

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Question

Solve for $α$ , which satisfy: ${max}_{θ ϵ R} {5 s i n θ + 3 s i n (θ - α)} = 7$

α = n π \pm \frac{π}{3}

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α = 2 n π \pm \frac{π}{6}

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α = 2 n π \pm \frac{π}{3}

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α = 2 n π \pm \frac{2 π}{3}

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Solution

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Similar questions

Which of the following statements are correct?

1 . if sin θ = sin α ⇒ θ = nπ + $(- 1)^{n}$ α where α ∈ [ - $\frac{π}{2}$ , $\frac{π}{2}$ ] n ∈ I

2 . if cos θ = cos α ⇒ 2nπ±α where α ∈ [0,π] n ∈ I

3 . if tan θ = tan α ⇒ θ = nπ + α where α ∈ (- $\frac{π}{2}$ , $\frac{π}{2}$ ) n ∈ I

Which of the following statements are correct?

1 . if sin θ = sin α ⇒ θ = nπ + $(- 1)^{n}$ α where α ∈ [ - $\frac{π}{2}$ , $\frac{π}{2}$ ] n ∈ I

2 . if cos θ = cos α ⇒ 2nπ±α where α ∈ [0,π] n ∈ I

3 . if tan θ = tan α ⇒ θ = nπ + α where α ∈ (- $\frac{π}{2}$ , $\frac{π}{2}$ ) n ∈ I

The general solution of $s i n x = s i n α, α ϵ [- \frac{π}{2}, \frac{π}{2}]$ is

The general solution of $t a n x = t a n α, α ϵ (- \frac{π}{2}, \frac{π}{2})$ is

\begin{matrix} Column I & Column II a. For θ \in R, if max {5 sin θ + 3 sin (θ - α)} = 7, then the set of possible values of α is & p. 2 n π + \frac{3 π}{4}, n \in Z b. x \neq \frac{n π}{2} and (cos x)^{{sin}^{2} x - 3 sin x + 2} = 1 & q. 2 n π \pm \frac{π}{3}, n \in Z c. \sqrt{sin x} + 2^{1 / 4} cos x = 0 & r. 2 n π + {cos}^{- 1} (\frac{1}{3}), n \in Z d. {log}_{5} tan x = ({log}_{5} 4) ({log}_{4} (3 sin x)) & s. no solution \end{matrix}

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