Question

Solve for x:
3(3x−12x+3)−2(2x+33x−1)=5 where x is not equal to 13,−32.

Answer 1

$$\begin{gathered} 3\left(3\mathrm{x}-12\mathrm{x}+3\right)-2\left(2\mathrm{x}+33\mathrm{x}-1\right)=5 \\ \Rightarrow 3\left(-9\mathrm{x}+3\right)-2\left(35\mathrm{x}-1\right)=5 \\ \Rightarrow -27\mathrm{x}+9-70\mathrm{x}+2=5 \\ \Rightarrow -97\mathrm{x}=5-11 \\ \Rightarrow -97\mathrm{x}=-6 \\ \Rightarrow \mathbf{x}\mathbf{=}\frac{\mathbf{6}}{\mathbf{97}} \end{gathered}$$