Question

Solve for $t$: $\frac{3t-2}{4}-\frac{2t+3}{3}=\frac{2}{3}-t$

Answer 1

$\frac{3t-2}{4}-\frac{2t+3}{3}=\frac{2}{3}-t$

$\Rightarrow \frac{3(3t-2)-4(2t+3)}{12}=\frac{2-3t}{3}$

$\Rightarrow \frac{9t-6-8t-12}{12}=\frac{2-3t}{3}$

$\Rightarrow \frac{t-18}{4}=2-3t$

$\Rightarrow t-18=8-12t$

$\Rightarrow 13t=26$

$\therefore t=\frac{26}{13}=2$