Solve for $x : 15 x^{2} - 7 x - 36 = 0$

\frac{5}{9}, - \frac{4}{3}

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\frac{9}{5}, - \frac{4}{3}

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\frac{9}{5}, - \frac{3}{4}

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Solution

The correct option is D $\frac{9}{5}, - \frac{4}{3}$
Here the quadratic equation is $15 x^{2} - 7 x - 36 = 0$
$\Rightarrow 15 x^{2} - 27 x + 20 x - 36$
$\Rightarrow 3 x (5 x - 9) + 4 (5 x - 9)$
$\Rightarrow (3 x + 4) (5 x - 9)$
$\Rightarrow 3 x + 4 = 0$
$\Rightarrow 3 x = - 4$
$\Rightarrow x = - \frac{4}{3}$ or
$\Rightarrow 5 x - 9 = 0$
$\Rightarrow 5 x = 9$
$\Rightarrow x = \frac{9}{5}$

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