Solve for $x$ :
$2 x^{2} + 5 x - 7 = 0$ .

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Solution

Now,
$2 x^{2} + 5 x - 7 = 0$
or, $2 x^{2} + 7 x - 2 x - 7 = 0$
or, $x (2 x + 7) - 1 (2 x + 7) = 0$
or, $(x - 1) (2 x + 7) = 0$
or, $x = 1, - \frac{7}{2}$ .

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