Solve for x : (2x-2)+(3x-3)+(9x-9) = 1

$[2 M a r k s]$

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Solution

(2x-2)+(3x-3)+(9x-9) = 1

2x – 2 + 3x – 3 + 9x – 9 = 1

$[1 M a r k]$

14x – 14 = 1

14x = 1 + 14

x = 15/14

$[1 M a r k]$

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$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Solve the following equation:

$\frac{2 x}{x - 3} + \frac{1}{2 x + 3} + \frac{3 x + 9}{(x - 3) (2 x + 3)} = 0; x \neq 3, x \neq - \frac{3}{2}$

Q. Solve :

\frac{2 x - 1}{x + 3} + \frac{1 - 2 x}{x - 3} = \frac{4 - 3 x}{x^{2} - 9}

Q. Solve

\frac{2 x}{x - 3} + \frac{1}{2 x + 3} + \frac{3 x + 9}{(x - 3) (2 x + 3)} = 0;

x \neq 3, x \neq \frac{- 3}{2}

Q. Solve:

x + 6 - 3 x - 5 - 2 (x - 5) = 2 x - 9 - 2 x + 5 - 3 (x + 1)

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Solve for x : (2x-2)+(3x-3)+(9x-9) = 1 [2 Marks]

(2x-2)+(3x-3)+(9x-9) = 1 2x – 2 + 3x – 3 + 9x – 9 = 1 [1 Mark] 14x – 14 = 1 14x = 1 + 14 x = 15/14 [1 Mark]

Solve for x : (2x-2)+(3x-3)+(9x-9) = 1

$[2 M a r k s]$

(2x-2)+(3x-3)+(9x-9) = 1

2x – 2 + 3x – 3 + 9x – 9 = 1

$[1 M a r k]$

14x – 14 = 1

14x = 1 + 14

x = 15/14

$[1 M a r k]$