Solve for $x$ : $2 x^{2} + x - 6 = 0$

$x = - 2, - \frac{3}{2}$

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$x = - 2, \frac{3}{2}$

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$x = - 2, \frac{5}{2}$

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$x = 2, \frac{3}{2}$

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Solution

The correct option is B
$x = - 2, \frac{3}{2}$

Given,
$2 x^{2} + x - 6 = 0 \Rightarrow 2 x^{2} + 4 x - 3 x - 6 = 0 \Rightarrow 2 x (x + 2) - 3 (x + 2) = 0 \Rightarrow (x + 2) (2 x - 3) = 0$

$\Rightarrow x = - 2, \frac{3}{2}$

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