Solve for x:
3(9x)<8(3x)+3
(0,81)
(−∞,1)
(−∞,−2)∪(−2,−1)∪(−1,0)
None of these.
Put 3x=t to obtain 3t2−8t−3<0⇒(3t+1)(t−3)<0As 3t+1>0, we get t<3 or x<1
Find the range of x for the following expression:
∣∣x2−3x+2x2+3x+2∣∣≥1
log3(x3)+log1/9(x)<1