Question

Solve for $x$ : $3x^2-2x+2=0$

Answer 1

$3x^2-2x+2=0$

Here, $a=3,b=-2,c=2$

$\Rightarrow$ $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-(-2)\pm \sqrt{(-2{)}^2-4(3\left)\right(2)}}{2\left(3\right)}$

$=\frac{2\pm \sqrt{4-24}}{6}$

$=\frac{2\pm \sqrt{-20}}{6}$

$=\frac{2\pm \sqrt{20}i}{6}$

$\therefore$ $x=\frac{2+\sqrt{20}i}{6}$ and $x=\frac{2-\sqrt{20}i}{6}$