Solve for $x : (3 x + 4) (2 x - 5) - 122 = (6 x - 1) (x + 10)$

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $- 2$
$(3 x + 4) (2 x - 5) - 122 = (6 x - 1) (x + 10)$
On multiplication, we get
$6 x^{2} - 7 x - 142 = 6 x^{2} + 59 x - 10$
$= - 7 x - 142 = 59 x - 10$
or $- 132 = 66 x$
$∴ x = - 2$

Suggest Corrections

Similar questions

(3 x + 4) (2 x - 5) = (6 x - 17) (x + 10)

x :

2 (x + 1) (x + 3) + 8 = (2 x + 1) (x + 5)

\frac{x - 1}{x - 2} + \frac{x - 3}{x - 4} = 3 \frac{1}{3}; x \neq 2, 4

\frac{1}{x} - \frac{1}{x - 2} = 3, x \neq 0, 2

x + \frac{1}{x} = 3, x \neq 0

\frac{16}{x} - 1 = \frac{15}{x + 1}, x \neq 0, - 1

\frac{1}{x - 3} - \frac{1}{x + 5} = \frac{1}{6}, x \neq 3, - 5

(x - 3) (x - 4)^{2} (x - 5) - 6 = 0

Join BYJU'S Learning Program