Solve for x:
$3 x (4 x + 1) = 9$

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Solution

$3 x (4 x + 1) = 9$
$12 x^{2} + 3 x - 9 = 0$
$12 x^{2} + 12 x - 9 x - 9 = 0$
$12 x (x + 1) - 9 (x + 1) = 0$
$(x + 1) (12 x - 9) = 0$
$x = - 1, \frac{9}{12}$

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