Solve for x

4^x-1* (0.5)^3-2x=(1/8)^x

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Solution

4^x-1* (0.5)^3-2x=(1/8)^x
2^2(x-1)* (5/10)^3-2x= (1/2^3)^x
2^2x-2* (1/2)^3-2x= (2)^-3x
2^2x-2* 2^-(3-2x)= (2)^-3x
2^2x-2-3+2x= 2^-3x
2x-2-3+2x = -3x
4x+3x = 5
7x = 5
x = 5/7 Ans.

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