Question

Solve for $x$:
$6x^2+5x-1=0$

Answer 1

$6x^2+5x-1=0$

$6x^2-x+6x-1=0$

$x(6x-1)+1(6x-1)=0$

$(6x-1)(x+1)=0$

Hence either bx - 1, or ,x = 1 = 0

$\Rightarrow bx-1=0\Rightarrow x=1/6.$ and

$x+1=0\Rightarrow x=-1$

$\therefore x=\frac{1}{6}$ or x = - 1