Solve for $x : 7 < | x - 3 | < 11$

10 < x < 11

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- 8 < x < - 4

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- 8 < x < 14

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- 8 < x < - 4

10 < x < 14

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Solution

The correct option is B $- 8 < x < - 4$ or $10 < x < 14$
Given,

$7 < | x - 3 | < 11$

$7 < | x - 3 | a n d | x - 3 | < 11$

$\Rightarrow (x < - 4 o r x > 10) a n d - 8 < x < 14$

$- 8 < x < - 4 o r 10 < x < 14$

$∴ (- 8, - 4) \cup (10, 14)$

Suggest Corrections

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