Solve for x 9^x+6^x=2.4^x (1)0 (2)1 (3)+-2 (4)-1

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x^{2} + 2 \sqrt{x^{2} + 6 x} = 24 - 6 x

6^{x} = \frac{1}{216}

2^{x} = 4^{2 x + 1}

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\frac{6 x + 1}{3} + 1 = \frac{x - 3}{6}

f (x) = \frac{1}{6 x - x^{2} - 5}

6 x + 1 = 3 (x - 1) + 7

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