Solve for $x : 9 x^{4} - 27 x^{2} - 36 = 0$

9 (x^{2} - 4) (x^{2} + 1)

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(x^{2} - 4) (9 x^{2} + 1)

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9 (x^{2} + 4) (x^{2} - 1)

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9 (x^{2} - 4) (x^{2} - 1)

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Solution

The correct option is A $9 (x^{2} - 4) (x^{2} + 1)$
$9 x^{4} - 27 x^{2} - 36 = 0$
$\Rightarrow 9 [x^{4} - 3 x^{2} - 4] = 0$
$\Rightarrow 9 [x^{2} (x^{2} - 4) + 1 (x^{2} - 4)]$
$\Rightarrow 9 (x^{2} - 4) (x^{2} + 1)$

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