1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Mathematics
Elimination Method of Finding Solution of a Pair of Linear Equations
Solve for x...
Question
Solve for
x
and
y
:
11
x
+
15
y
+
23
=
0
,
7
x
−
2
y
−
20
=
0
Open in App
Solution
11
x
+
15
y
+
23
=
0........
(
1
)
7
x
−
2
y
−
20
=
0........
(
2
)
After multiplying equation
(
1
)
by
2
and equation
(
2
)
by
15
on addition we get,
2
(
11
x
+
15
y
+
23
)
+
15
(
7
x
−
2
y
−
20
)
=
0
22
x
+
30
y
+
46
+
105
x
−
30
y
−
300
=
0
127
x
−
254
=
0
127
x
=
254
x
=
2
Substitute
x
=
2
in equation
(
1
)
,
22
+
15
y
+
23
=
0
15
y
+
45
=
0
15
y
=
−
45
y
=
−
3
Suggest Corrections
0
Similar questions
Q.
11
x
+
15
y
+
23
=
0
,
7
x
−
2
y
−
20
=
0
.
Q.
Solve:
7
x
−
2
y
=
20
11
x
+
15
y
+
23
=
0
Q.
Solve the equation by elimination method
11
x
+
15
y
+
23
=
0
,
7
x
−
2
y
−
20
=
0
Q.
Solve the following systems of equations:
11
x
+
15
y
+
23
=
0
7
x
−
2
y
−
20
=
0
Q.
If the question is 11x + 15y +23 = 0 , 7x -2y -20= 0 Find x and y. In any this type of sum how can we now that first we have to find the value of x or y .
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Algebraic Solution
MATHEMATICS
Watch in App
Explore more
Elimination Method of Finding Solution of a Pair of Linear Equations
Standard X Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app