Question

Solve for x and y:

$3x-5y-19=0,-7x+3y+1=0.$

Answer 1

The given equations are.

$3x–5y–19=0$ ------------(1)

$-7x+3y+1=0$ ------------(2)

Multiplying (1) by 3 and (2) by 5, we get,

$9x–15y=57$--------(3)

$-35x+15y=-5$ ---------(4)

Adding (3) and (4), we get

$-26x=52\Rightarrow x=-2$

Substituting $x=-2$ in (1), we get

$3(-2)–5y=19\Rightarrow -6–5y=19$

$-5y=19+6\Rightarrow -5y=25\Rightarrow y=-5$

$x=-2$ and $y=-5$