Question

Solve for x and y:

$7(y+3)-2(x+2)=14,4(y-2)+3(x-3)=2$

Answer 1

The given system of equation is

$7(y+3)-2(x+2)=14$…………………………. (i)

$4(y-2)+3(x-3)=2$………………………………..(ii)

$From\left(i\right)$

$7y+21-2x-4=14$

$7y=14+4-21+2x$

$=y=\frac{2x-3}{7}$

$From\left(ii\right)$

$=4y-8+3x-9=2$

$=4y+3x-17-2=0$

$=4y+3x-19=0\dots \dots \dots \dots \dots ..\left(iii\right)$

Substituting the value of y in equation (iii)

$=4\left(\frac{2x-3}{7}\right)+3x-19=0$

$=8x-12+21x-133=0$

$=29x=145$

$=x=5$

Putting the value of x in the above equation

$=y=1$

The value of x and y are 5 and 1 respectively