Solve for x and y :
ax + by - 2a + 3b = 0
and bx - ay = 3a + 2b

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Solution

$a x + b y = 2 a - 3 b - (i) b x - a y = 3 a + 2 b - (i i) (i) \times a (i) \times b$
Substituting $x = 2$ in $(i)$
$a (2) + b y - 2 a + 3 b = 0 b y = - 3 b y = - 3 ∴ x = 2, y = - 3$

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