CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve for x and y by using method of substitution :
0.2x+0.3y=1.3; 0.4x+0.5y=2.3

A
2,3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2,3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2,3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2,3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2,3
0.2x+0.3y=1.32x+3y=13
x=133y2
and
0.4x+0.5y=2.34x+5y=23
4(133y2)+5y=23
266y+5y=23
3=y
x=133×32=2

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon