solve for x and y: (\log x)/3=(\log y)/2 and \log (xy)=5

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y

{log}_{100} | x + y | = \frac{1}{2}, {log}_{10} y - {log}_{10} | x | = {log}_{100} 4

Solve for x and y; if $x > 0$ and $y > 0$ :
$l o g x y = l o g \frac{x}{y} + 2 l o g 2 = 2$ .

(x, y)

{log}_{100} | x + y | = \frac{1}{2}, {log}_{10} y - {log}_{10} | x | = {log}_{100} 4

log (x + y) = log x y + a

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