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Byju's Answer
Standard XII
Mathematics
Modulus of a Complex Number
Solve for x...
Question
Solve for
x
:
3
x
−
2
−
1
<
0
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Solution
3
x
−
2
−
1
<
0
=
>
3
x
−
2
<
1
=
>
3
<
x
−
2
=
>
x
−
2
>
3
=
>
x
>
3
+
2
=
>
x
>
5
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Solve for x :
(ii)
1
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Solve for x:
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Solve
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