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Solving Linear Equations Using Transpose of Terms

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Question

Solve for $x$ $\frac{4 x + 3}{2 x - 5} < 6$

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Solution

$\frac{4 x + 3}{2 x - 5} < 6$
$=> 4 x + 3 < 6 (2 x - 5)$
$=> 4 x + 3 < 12 x - 30$
$=> 12 x - 4 x > 30 + 3$
$=> 8 x > 33$
$=> x > \frac{33}{8}$

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