Question

Solve for $x$:

$3(2^x+1)-2^{x+2}+5=0$.

Answer 1

$3(2^x+1)-2^{x+2}+5=0$
$\Rightarrow {3.2}^x+3-2^{x+2}+5=0$
$\Rightarrow {3.2}^x-2^x{.2}^2=-8$
$\Rightarrow 2^x(3^1-2^2)=-8$
$\Rightarrow 2^x(3-4)=-8$
$\Rightarrow 2^x=\frac{-8}{-1}$
$\Rightarrow 2^x=8$

$\Rightarrow 2^x=2^3$

Hence, $x=3$