1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Mathematics
Modulus Function
Solve for x...
Question
Solve for
x
:
16
x
−
1
=
15
x
+
1
;
x
≠
0
,
−
1
Open in App
Solution
16
x
−
1
=
15
x
+
1
Cross multiplying,
16
−
x
x
=
15
x
+
1
⇒
(
16
−
x
)
(
x
+
1
)
=
15
x
⇒
16
x
+
16
−
x
2
−
x
=
15
x
⇒
16
=
x
2
⇒
x
=
±
4
Suggest Corrections
1
Similar questions
Q.
Solve for x, the roots are
+
4
,
−
4
:
16
x
−
1
=
15
x
+
1
,
x
≠
0
,
−
1
Q.
Solve the following quadratic equations by factorization:
16
x
-
1
=
15
x
+
1
;
x
≠
0
,
-
1
Q.
Solve for x:
(i)
x
-
1
x
-
2
+
x
-
3
x
-
4
=
3
1
3
;
x
≠
2
,
4
(ii)
1
x
-
1
x
-
2
=
3
,
x
≠
0
,
2
(iii)
x
+
1
x
=
3
,
x
≠
0
(iv)
16
x
-
1
=
15
x
+
1
,
x
≠
0
,
-
1
(v)
1
x
-
3
-
1
x
+
5
=
1
6
,
x
≠
3
,
-
5