Question

Solve for x ; $\frac{2^{x-3}}{8^{-x}}=\frac{32}{4^{\left(1/2\right)x}}$

• A. $2\frac{1}{5}$
• B. $1\frac{1}{5}$
• C. $3\frac{1}{5}$
• D. $1\frac{3}{5}$

Answer 1

The correct option is D $1\frac{3}{5}$

$\frac{2^{x-3}}{8^{-x}}=\frac{32}{4^{\left(1/2\right)x}}$
$\frac{2^{x-3}}{2^{-3x}}=\frac{2^5}{2^{\left(2/2\right)x}}$\\
$2^{x-3+3x}=2^{5-x}$
$4x-3=5-x$
$5x=8$
$x=1\frac{3}{5}$
Answer (D) $1\frac{3}{5}$