Solve for x-3x-1-16-2x-3-7-x-3-8-3x-1-14-

The correct option is A 5 Given, 3x+116 + 2x 37 = x+38 + 3x 114 ⇒(3x+1)× 7 + (2x 3)× 1616× 7= (x+3)× 14 + (3x 1)× 88× 14 ⇒ 21x+7 + 32x 48 ...

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Byju's Answer

Standard X

Mathematics

Multiplying/Dividing a Negative Entity

Solve for x...

Question

Solve for $x : \frac{(3 x + 1)}{16} + \frac{(2 x - 3)}{7} = \frac{(x + 3)}{8} + \frac{(3 x - 1)}{14}$ .

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Solution

The correct option is A $5$
Given, $\frac{3 x + 1}{16} + \frac{2 x - 3}{7} = \frac{x + 3}{8} + \frac{3 x - 1}{14}$
$\Rightarrow \frac{(3 x + 1) \times 7 + (2 x - 3) \times 16}{16 \times 7} = \frac{(x + 3) \times 14 + (3 x - 1) \times 8}{8 \times 14}$
$\Rightarrow 21 x + 7 + 32 x - 48 = 14 x + 42 + 24 x - 8$
$\Rightarrow (21 + 32 - 14 - 24) x = 42 - 8 - 7 + 48$
$\Rightarrow 15 x = 75$
$\Rightarrow x = 5$

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Similar questions

Solve each of the following equations and also verify your solution :

$\frac{(3 x + 1)}{16} + \frac{(2 x - 3)}{7} = \frac{(x + 3)}{8} + \frac{(3 x - 1)}{14}$

Q. What is the value of

x

in the given equation?

\frac{(3 x + 1)}{16} + \frac{(2 x - 3)}{7} = \frac{(x + 3)}{8} + \frac{(3 x - 1)}{14}

Solve the equations:

(i) 5x = 3x + 24;

(ii) 8t + 5 = 2t − 31;

(iii) 7x − 10 = 4x + 11;

(iv) 4z + 3 = 6 + 2z;

(v) 2x − 1 = 14 − x;

(vi) 6x + 1 = 3(x − 1) + 7;

(vii) ;

(viii) ;

(ix) 3(x + 1) = 12 + 4 (x − 1);

(x) 2x − 5 = 3(x − 5);

(xi) 6(1 − 4x) + 7(2 + 5x) = 53;

(xii) 3(x + 6) + 2 (x + 3) = 64;

(xiii) ;

(xiv) .

Solve for x and y:

$\frac{x + y - 8}{2} = \frac{x + 2 y - 14}{3} = \frac{3 x + y - 12}{11}$

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

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Solve for x:(3x+1)16+(2x−3)7=(x+3)8+(3x−1)14.

The correct option is A 5Given, 3x+116+2x−37=x+38+3x−114⇒(3x+1)×7+(2x−3)×1616×7=(x+3)×14+(3x−1)×88×14⇒21x+7+32x−48=14x+42+24x−8⇒(21+32−14−24)x=42−8−7+48⇒15x=75⇒x=5

Solve for $x : \frac{(3 x + 1)}{16} + \frac{(2 x - 3)}{7} = \frac{(x + 3)}{8} + \frac{(3 x - 1)}{14}$ .