Question

Solve for x: $\frac{4+2x}{3}\ge \frac{x}{2}-3$

• A. [26,∞)
• B. [-26,∞)
• C. [25,∞)
• D. [-25,∞)

Answer 1

The correct option is B [-26,∞)

$\frac{4+2x}{3}\ge \frac{x}{2}-3$

$\Rightarrow \frac{4+2x}{3}\ge \frac{x-6}{2}$

$\Rightarrow \frac{4+2x}{3}-\frac{x-6}{2}\ge 0$

$\Rightarrow 8+4x-3x+18\ge 0$

$\Rightarrow x\ge -26$

$xϵ[-26,\infty )$
So, option b is correct.