Solve for xif 495 x -343-A- 3 - 10B- 3 - 20C- 5 - 21D- 3

The correct option is B 3/20 49^5x = √(343) (7^2)^5x = (7^3)^1/2 7^10x = 7^3/2 10x = 3/2 x = 3/20. Therefore, the value of x is 3/20. ...

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Natural Numbers

Solve for xif...

Question

Solve for $x$ if $49^{5 x} = \sqrt{343} .$

3/10

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3/20

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5/21

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Similar questions

2 x + 5 = 25

The expression $\frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}$ when simplified reduces to $a - b \sqrt{15}$

Then a + b is

\sqrt[3]{\frac{- 125}{343}}

(i) {(\frac{27}{125})}^{\frac{2}{3}} \times {(\frac{9}{25})}^{- \frac{3}{2}}

(i i) 7^{0} \times {(25)}^{- \frac{3}{2}} - 5^{- 3}

(i i i) {(\frac{16}{81})}^{- \frac{3}{4}} \times {(\frac{49}{9})}^{\frac{3}{2}} \div {(\frac{343}{216})}^{\frac{2}{3}}

343 a^{3} - b^{3} - 147 a^{2} b + 21 a b^{2}

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