Solve for $x$ if
(i) $x$ is 5 digit number
(ii) $x$ is divisible by $11$ and
(iii) $x$ has $^{'} 1^{'}$ in its units, hundreds and thousands and ten thousands.

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Solution

Let $z$ be the number in the ten's place.
Thus. $x = 111 z 1$
Now. $x$ is divisible by $11$
If $z = 1$ , then
$x = 11111$ , not divisible by $11$
If $z = 2$ , then
$x = 11121$ , not divisible by $11$
Thus, the number is $11121$

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Solve for x if(i) x is 5 digit number(ii) x is divisible by 11 and(iii) x has ′1′ in its units, hundreds and thousands and ten thousands.

Let z be the number in the ten's place.Thus. x=111z1Now. x is divisible by 11If z=1, then x=11111, not divisible by 11If z=2, then x=11121, not divisible by 11Thus, the number is 11121

Solve for $x$ if
(i) $x$ is 5 digit number
(ii) $x$ is divisible by $11$ and
(iii) $x$ has $^{'} 1^{'}$ in its units, hundreds and thousands and ten thousands.

Let $z$ be the number in the ten's place.
Thus. $x = 111 z 1$
Now. $x$ is divisible by $11$
If $z = 1$ , then
$x = 11111$ , not divisible by $11$
If $z = 2$ , then
$x = 11121$ , not divisible by $11$
Thus, the number is $11121$