Question

Solve for $x$ in $\frac{2-(3x-8)}{5-(4x-9)}=\frac{1}{2}$

Answer 1

$\frac{2-(3x-8)}{5-(4x-9)}=\frac{1}{2}$

$\frac{2-3x+8}{5-4x+9}=\frac{1}{2}$

$\Rightarrow 2(10-3x)=1(14-4x)$

$\Rightarrow 20-6x=14-4x$

$\Rightarrow 20-14=6x-4x$

$\Rightarrow 2x=6$

$\Rightarrow x=\frac{6}{2}=3$

Hence the correct answer is $x=3$.