Solve for x:

log (3x + 4) = 2

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Solution

$l o g (3 x + 4) = 2$

$3 x + 4 = 10^{2}$

$3 x + 4 = 100$

$3 x = 96$

$x = 32$

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$l o g_{3} (\frac{x}{3}) + l o g_{1 / 9} (x) < 1$

Solve for $x$ .
$\frac{x + 4}{x - 2} = \frac{4}{7}$

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\frac{1}{x + 2} + \frac{2}{x + 2} = \frac{4}{x + 4}

\frac{7 y + 4}{y + 2} = \frac{- 4}{3}

y : 2 y^{2} + 4 = 9 y

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