Solve for x:
$log (x + 3) + log (x - 3) = log 16$

3

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2

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4

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5

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Solution

The correct option is C $5$
$S i n c e, log [(x + 3) (x - 3)] = l o g 16 x^{2} - 3^{2} = 16 x^{2} = 16 + 9 = x^{2} = 25 ∴ x = \pm 5 b u t x \neq - 5 a s l o g h a s d o m a i n o f o n l y + v e v a l u e s ∴ x = 5$

Suggest Corrections

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log (x + 3) + log (x - 3) = log 16

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