Question

Solve for $x$:

${\sin }^{2}x+{\sin }^2{30}^{\circ }=1$

Answer 1

${\sin }^{2}x+{\sin }^{2}30=1$
${\sin }^{2}x+(\frac{1}{2}{)}^2=1$
${\sin }^{2}x+\frac{1}{4}=1$
${\sin }^{2}x=\frac{3}{4}$
$\sin x=\frac{\sqrt{3}}{2}$
$\sin x=\sin 60$
$x={60}^{\circ }$