Question

Solve for x:
$\sqrt{2}{x}^2+3x-9\sqrt{2}=0$.

Answer 1

Now,

$\sqrt{2}{x}^2+3x-9\sqrt{2}=0$

$\Rightarrow \sqrt{2}{x}^2+6x-3x-9\sqrt{2}=0$

$\Rightarrow \sqrt{2}x(x+3\sqrt{2})-3(x+3\sqrt{2})=0$

$\Rightarrow (x+3\sqrt{2})(\sqrt{2}x-3)=0$

$\Rightarrow x=-3\sqrt{2},\frac{3}{\sqrt{2}}$.