Solve for x - -7x2 - 6x - 13 -7 - 0

√(7x^2) 6x 13√(7)=0 √(7)x 6x 13√(7)=0 (√(7) 6)x=13√(7) x=13√(7)√(7) 6 ...

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Identities for Irrational Numbers

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Question

Solve for $x$ : $\sqrt{7 x^{2}} - 6 x - 13 \sqrt{7} = 0$

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\sqrt{2 x^{2} + 5 x - 7} + \sqrt{3 (x^{2} - 7 x + 6)} - \sqrt{7 x^{2} - 6 x - 1} = 0

Solve for $x; \sqrt{6 x + 7} - (2 x - 7) = 0$

x^{2} + 6 x + 13 > 0

Solve for x and y:

$\frac{1}{2 x} + \frac{1}{3 y} = 2, \frac{1}{3 x} + \frac{1}{2 y} = \frac{13}{6} (x \neq 0, y \neq 0) .$

x^{2} - 6 x + 7 = 0

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