Solve for x -tan -11- x -1- x -1-2tan -1 x - x -0A- -3B- 1C- -1D- 1-3

The correct option is D 1/√(3) π/3 tan^ 1x=1/2tan^ 1x ⇒ tan^ 1x = π/6 x=1/√(3) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Standard Formulae - 1

Solve for x ....

Question

Solve for x.

$t a n^{- 1} (\frac{1 - x}{1 + x}) = \frac{1}{2} t a n^{- 1} x, x > 0$

$\sqrt{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$1$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$- 1$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{1}{\sqrt{3}}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

Solve for x.

$t a n^{- 1} (\frac{1 - x}{1 + x}) = \frac{1}{2} t a n^{- 1} x, x > 0$

x

{tan}^{- 1} (\frac{1 - x}{1 + x}) = \frac{1}{2} {tan}^{- 1} x, x > 0

Solve the following equation for x:

$t a n^{- 1} \frac{1 - x}{1 + x} = \frac{1}{2} t a n^{- 1} x, (x > 0)$ .

{tan}^{- 1} (\frac{1 - x}{1 + x}) = \frac{1}{2} {tan}^{- 1} x

2 t a n^{- 1} x = s i n^{- 1} \frac{2 x}{1 + x^{2}}

Join BYJU'S Learning Program