Question

Solve for x, the roots are $+4$, $-4$:
$\frac{16}{x}-1=\frac{15}{x+1},x\ne 0,-1$

• A. True
• B. False

Answer 1

The correct option is A True

$\frac{16}{x}-1=\frac{15}{x+1}$

$\Rightarrow$ $16(x+1)-x(x+1)=15x$

$\Rightarrow$ $16x+16-x^2-x=15x$

$\Rightarrow$ $x^2-16=0$

$\Rightarrow$ $x^2=16$

$\Rightarrow$ $x=\pm 4$

$\therefore$ We can see, roots given in question are correct.