Question

Solve for x using the quadratic formula. Write your answer correct to two significant figures:

$(x-1{)}^2-3x+4=0$

Answer 1

$(x-1{)}^2-3x+4=0\Rightarrow x^2-5x+5=0$

Here, $a=1,b=-5,c=+5$

So, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{5\pm \sqrt{(-5{)}^2-4\times 1\times 5}}{2\times 1}=\frac{5\pm \sqrt{5}}{2}=\frac{5\pm 2.236}{2}\Rightarrow x=3.62orx=1.38$