Solve for $x$ : $x^{2} - 3 x - 7 = 0$

Open in App

Solution

$\Rightarrow$ The given quadratic equation is $x^{2} - 3 x - 7 = 0$ ,

comparing it with $a x^{2} + b x + c = 0$

Here, $a = 1, b = - 3, c = - 7$

$\Rightarrow$ $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

$= \frac{- (- 3) \pm \sqrt{(- 3)^{2} - 4 (1) (- 7)}}{2 (1)}$

$= \frac{3 \pm \sqrt{9 + 28}}{2}$

$= \frac{3 \pm \sqrt{37}}{2}$

$x = \frac{3 + \sqrt{37}}{2}$ and $x = \frac{3 - \sqrt{37}}{2}$

Suggest Corrections

Similar questions

Solve following equation for $x$ :
$x^{2} - 3 x - 10 = 0$

x^{2} + 3 x + 5 = 0

x

| (x^{2} + 2 x + 2) + (3 x + 7) | < | x^{2} + 2 x + 2 | + | 3 x + 7 |

x

\frac{1}{5} (3 x - 2) - \frac{1}{3} (x + 7) + 1 = 0

\frac{x^{2} - 5 x + 7}{- 2 x^{2} + 3 x + 2} > 0

Join BYJU'S Learning Program