Solve for $x$ :
$x^{2} + 3 x + 1 = (x - 2)^{2}$ .

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Solution

Now,

$x^{2} + 3 x + 1 = (x - 2)^{2}$

or, $x^{2} + 3 x + 1 = x^{2} - 4 x + 4$

or, $7 x = 3$

or, $x = \frac{3}{7}$ .

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