Solve for x :
$x^{2} - 3 x - 10 = 0$

5, - 2

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2, - 5

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2, 5

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None of the above

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Solution

The correct option is D $5, - 2$
$x^{2} - 3 x - 10 = 0$
$x^{2} - 5 x + 2 x - 10 = 0$
$x (x - 5) + 2 (x - 5) = 0$
$(x - 5) (x + 2) = 0$
$x = 5, - 2$

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Similar questions

Solve for $- 2 x + 5 \leq 10$

Find the interval of $x$ such that $∣ ∣ \frac{x^{2} - 3 x - 1}{x^{2} + x + 1} ∣ ∣ < 3$ is satisfied is

x^{2} + 3 x + 5 = 0

x

(3 x - 5)^{2} + (3 x + 5)^{2}

(18 x + 10) (x - 2)

\frac{2}{x^{2}} - \frac{5}{x} + 2 = 0

\frac{1}{x} - \frac{1}{x - 2} = 3 x \neq 0, 2

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