Solve for x: $(x^{2} - 4 x + 3) = 0$

Open in App

Solution

$\begin{matrix} W e h a v e x^{2} - 4 x + 3 = 0 \Rightarrow x^{2} - 3 x - x + 3 = 0 \Rightarrow x (x - 3) - 1 (x - 3) = 0 \Rightarrow (x - 3) (x - 1) = 0 \Rightarrow x - 3 = 0 a n d x - 1 = 0 ∴ x = 3 a n d x = 1 H e n c e, t h e v a l u e o f x i s 1 & 3. \end{matrix}$

Suggest Corrections

Similar questions

x

| x^{2} - 4 x + 3 | = | x^{2} - 2 x + 1 |

x : 4 {(x - \frac{1}{x})}^{2} + 8 (x + \frac{1}{x}) = 29, x \neq 0.

x^{2} - 4 x + 1 + 3 = 0

∣ ∣ x^{2} + 4 x + 3 ∣ ∣ + 2 x + 5 = 0

x^{2} + 2 | x - 3 | - 10 < 0,

\frac{∣ ∣ x^{2} - 4 x ∣ ∣ + 3}{x^{2} + | x - 5 |} \geq 1

x

Join BYJU'S Learning Program