Question

Solve for x: $x^2$ - $5x$ + $8$ = $0$

• A. $x$ =$\frac{(-5+i\sqrt{7})}{2}$ and $x$ =$\frac{(-5-i\sqrt{7})}{2}$
• B. $x$ =$\frac{(5+i\sqrt{7})}{2}$ and $x$ =$\frac{(5-i\sqrt{7})}{2}$
• C. $x$ =$\frac{(-8+i\sqrt{5}7)}{2}$ and $x$ =$\frac{(8-i\sqrt{5}7)}{2}$
• D. $x$ =$\frac{(8+i\sqrt{5}7)}{2}$ and $x$ =$\frac{(8-i\sqrt{5}7)}{2}$

Answer 1

The correct option is B $x$ =$\frac{(5+i\sqrt{7})}{2}$ and $x$ =$\frac{(5-i\sqrt{7})}{2}$

$x^2-5x+8=0a=1,b=-5,c=8$ roots$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}x=\frac{5\pm \sqrt{25-32}}{2}x=\frac{5\pm i\sqrt{7}}{2}$